the adjacent angles of a parallelogram are (3x-120 and (52+2x0.find the angles of the parallelogram?
Is (52 + 2x0 supposed to be(52 + 2x) ?
Is (3x - 120 supposed to be (3x -12)
We can't come up with correct answers for you if the problems are typed wrong.
The sum of the two adjacent angles must be 180 degrees.
Use that fact to solve for x.
Then compute the angles.
If I guessed your errors correctly,
5x = 140 and x = 28.
That would make the angles 72 and 108 degrees.
Angle A= 72degree angle B= 108dgree angle C=72degree and angle D=108degree
72°,108°,72°,108°
To find the angles of a parallelogram, we need to use the property that the opposite angles of a parallelogram are congruent.
Let's denote the given adjacent angles as angle A and angle B. According to the question, angle A is represented as (3x-120) and angle B is represented as (52+2x).
Since angle A and angle B are adjacent angles, they form a straight line. Thus, the sum of their measures is 180 degrees.
So, we can set up the equation:
(3x-120) + (52+2x) = 180
Now we can solve this equation to find the value of x:
3x + 52 + 2x - 120 = 180
5x - 68 = 180
5x = 180 + 68
5x = 248
x = 248/5
x = 49.6
Now, we substitute the value of x back into the expressions for angle A and angle B to find their measures:
Angle A = 3x - 120 = 3(49.6) - 120 = 148.8 - 120 = 28.8 degrees
Angle B = 52 + 2x = 52 + 2(49.6) = 121.2 degrees
Therefore, the measures of the angles of the parallelogram are:
Angle A = 28.8 degrees
Angle B = 121.2 degrees