Calculus
posted by Laura .
This is the questions I have trouble with :
Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the xaxis.
Anyone who can help? Not really sure how to even begin!
Thanks

Surface area will be y dx dTheta
from x 0 to 1, and theta from 0 to 2PI
Area= Int (Int) tanhx dx dtheta 
Area=2Pi(int from 0 to 1) y*sqrt(1+(y')^2)dx

Thanks so much! :)
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