Algebra II Please check-
posted by Jodi .
Please help-What is the equation of the ellipse with foci (0,6), (0,-6) and co-vertices (2,0),(-2,0)
Please explain the steps because I have 5 to do for homework-Thank you-I'm really stuck on this
I thought the answer would be x^2/4 + y^2/40 = 1 but that can't be because the choices are:
x^2/1 + y^2/40 = 1 or x^2/1 + y^2/36
I'm really confused
I forgot to put that I think b= 2
c=6, so therefore
a^2-2^2 = 6^2
so a= 40, that' how I got to my equation
Your answer is correct.
It can't be correct my equation because that isn't a choice I was given-that's what I don't understand-thanks for trying to help though
Jodi,my answer was exactly identical to