An electron enters the region of a uniform electric field between two oppositely
charged parallel plates as shown, with an initial velocity of 3 x 106 m/s. The
electric field between the plates is measured to be E = 200N/C. The horizontal
length of the plates is 10cm.
a. Find the acceleration of the electron while it is in the electric field.
( and if the electron is negativly charged, but we don't know what type it is)
a. Acceleration is
a = e*E/m
e is the electron charge and m is the electron mass
b. Solve the equation
Since the electron's velocity component parallel to the plates remains the same as when it entered,
t = 0.10 m/(3*10^6 m/s)
how do we find out the electron charge and mass if we don't know what type it is?
sorry but that didn't really give me the answer because we don't know the electron mass or type??
To find the acceleration of the electron while it is in the electric field, we can use the equation:
F = q * E
Where F is the force experienced by the electron, q is the charge of the electron, and E is the electric field strength.
Since the electron is negatively charged, the charge, q, will be -1.6 x 10^-19 C (coulombs).
We are given the electric field strength, E = 200 N/C, and the force experienced by the electron is given by F = q * E.
Substituting the values, we get:
F = (-1.6 x 10^-19 C) * (200 N/C)
F = -3.2 x 10^-17 N
Since the force experienced by the electron is in the opposite direction of its velocity, the acceleration of the electron is given by:
a = F / m
Where m is the mass of the electron, which is approximately 9.1 x 10^-31 kg.
Substituting the values, we get:
a = (-3.2 x 10^-17 N) / (9.1 x 10^-31 kg)
a ≈ -3.5 x 10^13 m/s^2
So, the acceleration of the electron while it is in the electric field is approximately -3.5 x 10^13 m/s^2.