An electron enters the region of a uniform electric field between two oppositely

charged parallel plates as shown, with an initial velocity of 3 x 106 m/s. The
electric field between the plates is measured to be E = 200N/C. The horizontal
length of the plates is 10cm.
a. Find the acceleration of the electron while it is in the electric field.
( and if the electron is negativly charged, but we don't know what type it is)

To find the acceleration of the electron, we can use the equation for the force experienced by a charged particle in an electric field:

F = qE

Where:
- F is the force experienced by the particle,
- q is the charge of the particle, and
- E is the electric field strength.

In this case, since the electron is negatively charged, we know that the charge of the electron is -e, where e is the elementary charge. The elementary charge is approximately 1.6 x 10^-19 C.

Therefore, we can rewrite the equation as:

F = (-e)E

The force experienced by the electron in the electric field is given by:

F = m * a

Where:
- m is the mass of the electron, and
- a is the acceleration of the electron.

We rearrange the equation to solve for acceleration:

a = F / m = (-e)E / m

To calculate the acceleration, we need to know the mass of the electron, which is approximately 9.11 x 10^-31 kg.

Substituting the values into the equation:

a = ((-1.6 x 10^-19 C) * (200 N/C)) / (9.11 x 10^-31 kg)

a = -((1.6 x 200) / 9.11) x (10^-19 / 10^-31) m/s²

a = -(320 / 9.11) * (10^12) m/s²

a = -35.1 x 10^12 m/s²

Therefore, the acceleration of the electron while it is in the electric field is approximately -35.1 x 10^12 m/s². Note that since the acceleration is negative, it means that the electron will be accelerated in the opposite direction to the electric field.