HOW MANY MOLECULES OF CARBO DIOXIDE CO2 WILL BE PRODUCED WHEN 75 GRAMS OF GLUCOSE C6H12O6 ARE COMPLETELY OXIDIZED
Here is a worked example. Just follow the steps.
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To determine the number of CO2 molecules produced when a certain amount of glucose is oxidized, we need to use stoichiometry - the study of the quantitative relationships between reactants and products in a chemical reaction.
First, we need to write the balanced chemical equation for the oxidation of glucose (C6H12O6):
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the equation, we can see that for every molecule of glucose that is oxidized, 6 molecules of carbon dioxide are produced.
Next, we need to calculate the number of moles of glucose in 75 grams. To do this, we divide the mass of glucose by its molar mass. The molar mass of glucose (C6H12O6) is 180.16 g/mol (12.01 g/mol for carbon + 1.01 g/mol for hydrogen + 16.00 g/mol for oxygen, multiplied by the respective subscripts):
Number of moles of glucose = 75 g / 180.16 g/mol = 0.416 moles
Based on the balanced equation, we know that for every 1 mole of glucose, 6 moles of carbon dioxide are produced. Therefore, the number of moles of carbon dioxide produced can be calculated as:
Number of moles of CO2 = 0.416 moles × 6 = 2.496 moles
Finally, we can convert the number of moles of carbon dioxide to the number of molecules. 1 mole of any substance contains Avogadro's number of molecules, which is approximately 6.022 × 10^23 molecules/mol:
Number of molecules of CO2 = Number of moles of CO2 × Avogadro's number
= 2.496 moles × 6.022 × 10^23 molecules/mol
= 1.503 × 10^24 molecules
Therefore, when 75 grams of glucose are completely oxidized, approximately 1.503 × 10^24 molecules of carbon dioxide (CO2) are produced.