calculus

posted by .

Please help with this question. I have a general solution to a differential equation of 18y^3/2= TOP LINE OF FRACTION is 2(x^2-6x+23)^3/2 and this is divided by 3.plus Constant .I work out constant c to be zero. Is this correct? What is the particular solution for which y=2 when x=1. Then I need this particular solution in explicit form. Many thanks for help (with details). Best wishes.

  • calculus -

    Find C from equality
    18*(2^3/2)=(2(1^2-6*1+23)^3/2)/3 +C
    and substitute in the general solution.
    C is not 0.

    Can you write this differential equation?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. calculus

    Find the solution to the differential equation dy/dx = (x^3)/(y^2), where y(2) = 3 I have: The integral of: dy(y^2) = the integral of: dx(x^3) (y^3)/3 = (x^4)/4 The answer is supposed to come out to be y= the cube root of: ( 3/4x + …
  2. Calculus--> bobpursley

    How do you get m=0? from taking the second derivative?
  3. calculus-differential equation

    Consider the differential equation: (du/dt)=-u^2(t^3-t) a) Find the general solution to the above differential equation. (Write the answer in a form such that its numerator is 1 and its integration constant is C). u=?
  4. Integration-Calculus

    How do I integrate this? constant(1- z/[sqrt (z^2 + constant^2)] i know i can take the constant out so I have constant * integral 1- z/[sqrt (z^2 + constant^2)] and I know the integral of z/[sqrt (z^2 + constant^2)] is [ln z^2 + constant^2]/2
  5. calculus

    Please help with this question. I have a general solution to a differential equation of 18y^3/2= TOP LINE OF FRACTION is 2(x^2-6x+23)^3/2 and this is divided by 3. What is the particular solution for which y=2 when x=1. Then I need …
  6. Calculus

    Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x)=(x^2-6x+23). Please explain how I find the general solution to the differential equation dy/dx= 2/27(x-3)SQUARE ROOT BEGINS (x^2-6x+23)/y SQUARE ROOT ENDS (y>0). …
  7. calculus

    Please help. I have an implicit answer to a differential equation of 18y*sqrt(y)=(2(x^2-6x+23)^3/2)/3 plus arbitrary constant. What is the particular solution to this for which y=2 when x=1. And then express this particular solution …
  8. calculus

    Sorry to post this again, but I am still unable to understand it and need help. Please help.1) Using 3(x-3)(x^2-6x+23)^2 as the answer to differentiating f(x)=(x^2-6x+23)^3/2, which I have been able to do, I need to find the general …
  9. Help with differential eqs problem???? (Calculus)

    Consider the differential equation dy/dt=y-t a) Determine whether the following functions are solutions to the given differential equation. y(t) = t + 1 + 2e^t y(t) = t + 1 y(t) = t + 2 b) When you weigh bananas in a scale at the grocery …
  10. Differential equations,Calculus

    So I have the following differential equation. The general solution I have is: t=k(-1/r)+c I now need to find the particular solution when t=0 and the radius (r) = 1cm. So k is a constant which is approx 3.9 (5/4pi) So for the particular …

More Similar Questions