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Let (theta) be an angle in quadrant II such that csc(theta)=8/5 Find the exact value of tan(theta) and cos(theta).

  • trig -

    if csc Ø = 8/5
    sin Ø = 5/8
    I see a right-angled triangle with hypotenuse 8 and vertical side (the y) of 5
    By Pythagoras, the other side is √39

    in II both cosine and tangent are negative, so
    tanØ = -5/√39
    cosØ = -√39/8

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