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100,000J of heat is added to a 2.0KG of ice at -8degrees C. How much ice melts?

  • Physics -

    The heat of fusion is 80 cal/g = 335 J/g
    The specific heat of ice 2.11 J/g*degC

    To heat the ice to 0 C requires
    2000 g * 8 C *2.11 J/c*C = 33,760 J

    There is more than enough heat to melt all of the ice.

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