College Algebra
posted by Nancy .
SOLVE:
(3x5)^3
that's to the third power

Solving implies that you are dealing with an equation.
You did not give an equation. 
sorry ...it is cubing binomials and the avove problem

What is it equal to??
You still did not state the "equation"
It should look something like
(3x5)^3 = ????
are you just expanding (3x+5)^3
you could do it the long way by doing
(3x+5)(3x+5)(3x+5)
or you could use Pascal's triangle whose third row has coefficients 1 3 3 1
so
(3x+5)
= 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3
= 27x^3 + 135x^2 + 225x + 125 
great!!! thanks so much ...... you are a life saver!!!!! =)