You need 123 mL of 0.245 M NaOH solution for a certain experiment, and the only solution available in the lab is 1.252 M. How many mL OF THE 1.252 M NaOH would you need?

mL1 x M1 = mL2 x M2

123mL x 0.245 = mL2 x 1.252

To find out how many mL of the 1.252 M NaOH solution you would need, we can use the equation:

C₁V₁ = C₂V₂

Where:
C₁ = initial concentration of NaOH solution (1.252 M)
V₁ = initial volume of NaOH solution (unknown)
C₂ = final concentration of NaOH solution (0.245 M)
V₂ = final volume of NaOH solution (123 mL)

Rearranging the equation to solve for V₁, we have:

V₁ = (C₂ * V₂) / C₁

Substituting the values we have:

V₁ = (0.245 M * 123 mL) / 1.252 M

Now we can solve the equation:

V₁ = 30.135 mL

Therefore, you would need approximately 30.135 mL of the 1.252 M NaOH solution.