Post a New Question

algebra

posted by .

¿como se desarrolla? lo siguiente:

log(x-7/x-1)=1/2

lo antes posible por favor.

  • algebra -

    10^log(x-7/x-1) = 10^.5
    but
    10^log a = a
    so
    (x-7)/(x-1) = 10^.5 = sqrt 10 = 3.16
    so
    x-7 = 3.16(x-1)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question