# Calculus

posted by .

Find the limit.

lim x-->1 (x^3)-1/((5x^2)+2x-7)

• Calculus -

= lim (x-1)(x^2 + x + 1)/((x-1)(5x+7)) as x ---> 1
= lime (x^2 + x + 1)/(5x+7) , as x --> 1
= 3/12
= 1/4

• Calculus -

Thanks.

## Similar Questions

1. ### Calculus

How do I solve for lim h->0 (((a+h)^2 + 1)/(3(a+h)+7) - ((a^2 + 1)/3a + 7)) and then all divided by h?

Find k for which the limit below exists, and find the limit. lim x->1 (2x^2 + kx +4)/(x-1) Please show me how to do both procedures. Thanks
3. ### Calculus

Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x->0 (1+x)^(1/x) or e= lim as x->infinity (1+1/n)^n Am i able to substitute in x/n for x?
4. ### Calculus

Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x->0 (1+x)^(1/x) or e= lim as x->infinity (1+1/n)^n Am i able to substitute in x/n for x?
5. ### Calculus (Derivatives)

Show the steps to get the derivative function of -500/x by evaluating the limit. By limit, they are referring to the equation, lim h -> 0 (f(x + h)-f(x))/h
6. ### Precalc

find the following limit lim n->infinity 2+5n+4n^4/2n show steps please
7. ### Calculus

I have two similar problems that I need help completing. Please show all your work. Question: Find the limit L. Then use the å-ä definition to prove the limit is L. 1. lim (2x+5) x->3 2. lim 3 x->6 Thank you for your anticipated …
8. ### Calculus

Find if the limit exists. lim tan(x)/x x->0 Please show how you determined this. Thanks!

4. lim (tanx)= x->pi/3 -(sqrt3) 1 (sqrt3) ***-1 The limit does not exist. 5. lim |x|= x->-2 -2 ***2 0 -1 The limit does not exist. 6. lim [[x]]= x->9/2 (Remember that [[x]] represents the greatest integer function of x.) 4 …
10. ### Calculus

Find the limit. lim 5-x/(x^2-25) x-->5 Here is the work I have so far: lim 5-x/(x^2-25) = lim 5-x/(x-5)(x+5) x-->5 x-->5 lim (1/x+5) = lim 1/10 x-->5 x-->5 I just wanted to double check with someone and see if the answer …

More Similar Questions