A mirror creates an image of magnification −1/3. (a) Is the image upright or inverted? (b) If the object is 7.75 cm tall, what is the height of the image? State your answer with the correct sign. answer to part B should be in cm. thanks.

Image height = (-1/3)*7.75 = -2.58 cm

By convention, if the magnification is positive, the image is upright. If the magnification is negative, the image is inverted (upside down).

To determine whether the image formed by a mirror is upright or inverted, we can look at the sign of the magnification. In this case, the magnification is -1/3.

(a) Since the magnification is negative, the image is inverted.

To find the height of the image, we can use the magnification formula:

Magnification = Image height / Object height

Rearranging the formula, we can solve for the image height:

Image height = Magnification * Object height

Given that the object height is 7.75 cm and the magnification is -1/3:

Image height = (-1/3) * 7.75 cm

Multiplying -1/3 by 7.75 cm, we get:

Image height = -2.5833... cm

Rounding to two decimal places, the height of the image is approximately -2.58 cm (with the negative sign indicating that it is inverted).