posted by anonymous
Brit and Tara are standing 13.5 m apart on a dock when they observe a
sailboat moving parallel to the dock. When the boat is equidistant between
both girls, the angle of elevation to the top of its 8.0 m mast is for both
observers. Describe how you would calculate the angle, to the nearest degree,between Tara and the boat as viewed from Brit’s position. Justify your reasoning with calculations.
I THINK I DREW THE DIAGRAM BUT I'M NOT GETTING THE RIGHT ANSWER WHICH IS 47 DEGREES
Draw a hor. line and label it ABC with
B being the mid-point of the line. Draw
a ver line to point B and label the top
of the ver line point D. Draw a line from A to D and from C to D. We have
formed 2 congruent rt triangles with a
common ver side.
AB = BC = 13.75/2 = 6.75m.
BD = 8m.
tanA = BD/AB = 8/6.75 = 1.1852,
A = 50 Deg. = Angle of elevation.
i tried draw it your way and got 49 degrees. But i think we have to draw a 3
i meant i think we have to draw a 3D image of the triangle
the way you told me, i tried to do it and got a two congruent trianlges makin a 90 degrees angle