posted by Bimpe .
Use the Ideal Gas Law to determine the volume of CO2 produced at 25oC 1.5 atm of pressure from the combustion of 35 grams of C6H10.
balance the reaction equation:
2C6H10+17O2>>12CO2 + 10H20 check that.
so you get 12 moles CO2 for each 2 mole of C6H10
molesCO2=12/2 * moles C6H10=6*35/molmassC6H10
figure that out. Then,
V=nRT/P where n is moles CO2, you are given T (change it to K). Watch units of R, you are in kelvins, atm