When hydrochloric acid reacts with zinc metal, zinc chloride and hydrogen gas are produced. How many moles of hydrochloric acid are needed to react with 2.3 moles of zinc?
To determine the number of moles of hydrochloric acid needed to react with 2.3 moles of zinc, we can use the balanced equation for the reaction:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that it takes 2 moles of hydrochloric acid to react with 1 mole of zinc. Therefore, we can set up a ratio:
2 moles HCl / 1 mole Zn
Now we can calculate the number of moles of hydrochloric acid needed:
2.3 moles Zn x (2 moles HCl / 1 mole Zn) = 4.6 moles HCl
Therefore, 4.6 moles of hydrochloric acid are needed to react with 2.3 moles of zinc.
To determine the number of moles of hydrochloric acid needed to react with 2.3 moles of zinc, we need to use the balanced chemical equation for the reaction.
The balanced equation for the reaction between hydrochloric acid (HCl) and zinc (Zn) is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that 1 mole of zinc will react with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride and 1 mole of hydrogen gas.
Given that we have 2.3 moles of zinc, we can use the mole ratio from the balanced equation to determine the required moles of hydrochloric acid.
2.3 moles of zinc x (2 moles of HCl / 1 mole of Zn) = 4.6 moles of hydrochloric acid
Therefore, you would need 4.6 moles of hydrochloric acid to react with 2.3 moles of zinc.