# College Algebra

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Solve using Elimination or Substitution:

4x^2+9y^2=36
x+3y=3

• College Algebra -

Ideal for substitution
from the 2nd : x = 3 - 3y

sub into 1st

4(3-3y)^2 + 9y^2 = 36
36 - 72y + 36y^2 + 9y^2 = 36
45y^2 - 72y = 0
5y^2 - 8y = 0
y(5y-8) = 0
y = 0 or y = 8/5

if y = 0 , x = 3

if y = 8/5 , then x = 3-24/5 = -9/5

intersection points (3,0) and (-9/5, 8/5)

• College Algebra -

Thanks for the help.

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