@ 20 degrees C is 6g CuSO4 in 25g of H2O saturated or unsaturated? How do I figure this out?
Oh the given is supposed to be @20 degrees C solubility is 22g Cu SO4 /100g H2O
This should be saturated
When you divide 22g CuSO4 per 100 g H20 by 4. You get 5.5g of CuSO4 per 25g H2O.
Does this help?
To determine if a solution is saturated or unsaturated, you need to compare the amount of solute (CuSO4) present in the solution to the maximum amount that can dissolve at a specific temperature (in this case, 20 degrees C).
To figure this out, you can consult a solubility table or graph specific to CuSO4 and water at 20 degrees C. These references will provide you with the maximum solubility of CuSO4 in water at that temperature.
If the amount of CuSO4 in your solution (6g) is less than or equal to the maximum solubility, then the solution is saturated. If it exceeds the maximum solubility, the solution is considered supersaturated. However, if the amount of CuSO4 is less than the maximum solubility, the solution is unsaturated.
Keep in mind that solubility can be affected by other factors such as pressure and the presence of other solutes. So, always make sure your references are specifically for the temperature and conditions you are working with.