Im having a hard time figuring out this problem:
Use the function, y=-(x+1)^2 +2, to answer the following parts.
Find the y-intercept
y=-(0+1)^2 +2
y=-(1)^2 +2
y=-1+2
y=1 is my answer
Find the x-intercept
0=-(x+1)^2 +2
0=-((x^2)+(1^2))+2
0=-x^2 - 1 + 2
sq.rt(x^2)= sq.rt(1)
x=1 is my answer but im not sure about it.
Finding the vertex, increasing interval,and decreasing interval.
Is the vertex (-1,2)
Increasing interval (-2,1)
Decreasing interval(1,-2)
Do the x-intercept =1?
Your y-intercept is correct
for the x-intercept, you started correctly
0 = -(x+1)^2 + 2
(x+1)^1 = 2
take √ of both sides
x+1 = ± √2
x = -1 + √2 or x = -1 - √2
vertex is correct
increasing : x < -1
decreasing : x > 1
( change it to whatever notation you use to state the interval.)