How many mL of orange juice would be required to get the recommended daily allowance of 60 mg of vitamin C? (Concentration of vitamin C is .011 moles/L in 5.0 mL of juice).
The concentration of 0.11 mole/l does not depend upon the volume. I am assuming that you did not intend to write that 5.0 mL of juice contains 0.011 moles of Vitamin C.
You are going to need the molecular weight of Vitamin C (ascorbic acid) to convert mole to mg.
The formula is C6H8O6, so the molecular weight is 176 g/mol.
0.011 moles/l = 1.936 g/liter
is the Vitamin C concentration in mass/volume units.
60 mg of juice presumably has a volume of 60 ml, since OJ is mostly water.
For 60 mg of vitamin C, the MDA is
(60*10^-3 g)/(1.936 g/liter) = 0.031 liter. That is only about one ounce.
I don't believe that number. Recheck your assumptions and typing.
For the MDA of 60 mg, you would require
To find out how many milliliters (mL) of orange juice would be required to get the recommended daily allowance of 60 mg of vitamin C, we need to use the concentration of vitamin C in the juice and convert it to milligrams. Let's go step by step:
Step 1: Convert the given concentration to moles per milliliter (mol/mL):
Concentration of vitamin C = 0.011 moles/L (given)
To convert to moles per milliliter, divide by 1000 (since there are 1000 mL in a liter):
0.011 moles/L ÷ 1000 mL/L = 0.000011 mol/mL
Step 2: Convert moles to milligrams:
The molar mass of vitamin C (ascorbic acid) is approximately 176.12 g/mol, which means 1 mole of vitamin C weighs 176.12 grams (or 176,120 milligrams).
So, 0.000011 mol/mL × 176,120 mg/mol = 1.93732 mg/mL (approximately)
Step 3: Calculate the volume of orange juice required:
To find out how many milliliters (mL) of juice are required to get 60 mg of vitamin C, divide the recommended daily allowance (60 mg) by the concentration of vitamin C (1.93732 mg/mL):
60 mg ÷ 1.93732 mg/mL ≈ 30.99 mL
Therefore, approximately 30.99 milliliters of orange juice would be required to get the recommended daily allowance of 60 mg of vitamin C.