Algebra
posted by Mike .
Im having a hard time figuring out this problem:
Use the function, y=(x+1)^2 +2, to answer the following parts.
Find the yintercept
y=(0+1)^2 +2
y=(1)^2 +2
y=1+2
y=1 is my answer
Find the xintercept
0=(x+1)^2 +2
0=((x^2)+(1^2))+2
0=x^2  1 + 2
sq.rt(x^2)= sq.rt(1)
x=1 is my answer but im not sure about it.
I need help with:
Finding the vertex, increasing interval,and decreasing interval.

Algebra 
Mike
Is the vertex (1,2)
Increasing interval (2,1)
Decreasing interval(1,2)
Do the xintercept =1? 
Algebra 
Henry
1. y= 1 is correct.
2. Y = (X+1)^2 + 2 = 0,
(X+1)^2 = 2,
Divide both sides by 1:
(X+1)^2 = 2,
Take sqrt of both sides:
X+1 = sqrt2 = 1.4142,
X = 1.4142  1 = 0.4142. = xIntercept
3. V(1,2) is correct.
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