posted by Zarion Gibbs .
A 10.0-mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 16.5 XML of a 0.500M NaOH solution to reach the endpoint in a titration (where the moles of acid are equal to the moles of base). What is the molarity of the acetic acid solution
How many moles NaOH do you have? That is M x L = ??
How many moles acetic acid do you have? That will be the same thing; the problem tells you.
Concn acetic acid = moles/L soln. The problem gives you 10 mL which is 0.010 L so M = ??moles/0.010L = ??