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A 10.0-mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 16.5 XML of a 0.500M NaOH solution to reach the endpoint in a titration (where the moles of acid are equal to the moles of base). What is the molarity of the acetic acid solution

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    How many moles NaOH do you have? That is M x L = ??
    How many moles acetic acid do you have? That will be the same thing; the problem tells you.
    Concn acetic acid = moles/L soln. The problem gives you 10 mL which is 0.010 L so M = ??moles/0.010L = ??

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