1) If a total of 13.5 mol NaHCO3 and 4.5 mol of C6H8O7 react, how many moles of COs and NA3C6H5O7 will be produced?
3NaHCO3(aq) +C6H8O7(aq) -> 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq)
2) If 8,00 mol of NH3 reacted with 14.0 mol of O2, how many moles of H20 will be produced?
4NH3(g) +7O2(g) -> 4NO2 + 6H2O(g)
3) If 8.6 L of H2 reacted with 4.3L of O2 at STP, what is the volume of the gaseous water collected (assuming that none of it condenses)?
2H2(g) + O2(g) -> 2H2O(g)
4) How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7g Fe?
Fe2O3(s) + 3CO(g) -> 3CO2(g) + 2Fe(s)
5) How many liters of O2 are needed to react completely with 45.0L of H2S at STP?
2H2S(g) + 3O2(g) -> 2SO2(g) +2H20(g)
6) If 5.0 g of H2 are reacted with excess CO, how many grams of CH3OH are produced, based on a yield of 86%?
CO(g) + 2H2(g) -> CH3OH(l)
7) For the reaction 2Na(s) + Cl2(g) -> 2NaCl(g), how many grams of NaCl could be produced from 103.0g molecules of Na and 13.0 of Cl2 (at STP)?
8) Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of Hydrogen gas are formed when 48.7g of sodium are added to water?
2Na + 2H2O -> 2NaOH + H2
9) The decomposition of potassium chlorate yields oxygen gas. If the yield is 95%, how many grams of KClO3 are needed to produce 10.0L of O2
2KClO3(s) -> KCl(s) + 3O2(g)
10) 2H2S + 3O2(g) -> 2SO2(g) + 2H2)(g)
If the O2 was the excess reagent, 8.3 mol of H2S were consumed, and 137.1g of water were collected after the reaction has gone to complain, what is the percent yield of the reaction?
You can work most of these with standard stoichiometry. Here is a link.
http://www.jiskha.com/science/chemistry/stoichiometry.html
For limiting reagent problems, recognized as such by the fact that amounts for BOTH reactants are listed, are solved the same way but use the simple stoichiometric method twice, one with each reagent. The smaller value of moles is always the correct value to use for the product in these cases.
Post your work if you get stuck.