# College Chemistry

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If the voltage of the cell is -0.1288V at 25Celsius when [Pb2+]=0.1403M and the pressure of H2=1atm, what is the pH
Pb(s)+2H+(aq)<-> Pb2+(aq) +H2(g) E0 = 0.1260V

• College Chemistry -

Ecell = Eocell - (0.05916/2)log(Pb^2+)*PH2/(H^+)^2
Substitute and solve for H^+, then convert to pH.

• College Chemistry -

Thank you DrBob222

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