explain the probabilty of one event in a fair game with three possible outcome
If each outcome is due to chance, the probability of any one outcome = 1/3.
My daughter had the same problem today... The probability is 1/3...
If its a fair game then all of the factors have equal opportunity to occur.
The probability of one event in a fair game with three possible outcomes can be calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, there are three possible outcomes, so the denominator will be 3.
To determine the number of favorable outcomes, we need more information about the event in question. Can you please provide more details or specify the event you are referring to?
To calculate the probability of one event in a fair game with three possible outcomes, we need to determine the total number of outcomes and the number of favorable outcomes.
In this case, there are three possible outcomes. Let's say the event we are interested in is Outcome A.
To calculate the probability of Outcome A occurring, we need to determine the total number of outcomes and the number of favorable outcomes specifically related to Outcome A.
If all three outcomes (A, B, and C) are equally likely, each has a 1/3 chance of occurring. Therefore, the probability of Outcome A occurring is 1/3.
Here is the step-by-step process to calculate the probability:
Step 1: Identify the total number of outcomes. In this case, there are three possible outcomes, A, B, and C.
Step 2: Identify the number of favorable outcomes. Since we are interested in one specific outcome (Outcome A), there is only one favorable outcome.
Step 3: Calculate the probability by dividing the number of favorable outcomes by the total number of outcomes. In this case, 1 divided by 3, which equals 1/3 or approximately 0.333.
So, in a fair game with three possible outcomes, the probability of one specific event (Outcome A) occurring is 1/3.