Find the equation of a hyperbola of the form x squared / M - y squared / N = 1
the transverse axis is 12 and the foci from the center is 16
is the answer x squared / 36 - y squared / 220 = 1
so a = 6
c = 8
a^ + b^2 = c^2
b^2 = 64-36 = 28
then x^2/36 - y^2/28 = 1