Math
posted by Anonymous .
Find the equation of a hyperbola of the form x squared / M  y squared / N = 1
the transverse axis is 12 and the foci from the center is 16
is the answer x squared / 36  y squared / 220 = 1

so a = 6
c = 8
a^ + b^2 = c^2
b^2 = 6436 = 28
then x^2/36  y^2/28 = 1
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