please please please help me balance these two equations...

1. K2Cr2O7+H2C2O4.2H2O--> K[Cr(H20)2(C2O4)2].2H2O+CO2

2. K2Cr2O7+H2C2O4.2H2O--> K[Cr(H20)2(C2O4)2].3H2O+CO2

There are rules to follow in balancing redox equations. Here are the rules.

http://www.chemteam.info/Redox/Balance-HalfReactions-Acid.html

Here are some helpful hints.
#1. Both Cr change from +12 on the left to +6 on the right(FOR TWO Cr ATOMS on the right).
C changes from +6 on the left for both C atoms to +8 on the right for TWO C ATOMS of C in CO2. Note also that the C2O4 that is complexed with the Cr on the right does not undergo oxidation.

Common we need an example, its complexed. It doesnt change from 12 -6 it goes from 6-3 and carbon goes from 3-4. If the half reactions have to = the entire reaction then how is broken down. This is why students get irritated with posts like this. They know you wont be able to figure it out on your own.

To balance chemical equations, you need to ensure that there are equal numbers of atoms on both sides of the equation. Here's how you can balance each of these equations:

1. K2Cr2O7 + H2C2O4.2H2O --> K[Cr(H2O)2(C2O4)2].2H2O + CO2

First, let's balance the chromium (Cr) atoms. There are two chromium atoms on the left side and one on the right. To balance this, we can put a coefficient of 2 in front of K[Cr(H2O)2(C2O4)2].

2K2Cr2O7 + H2C2O4.2H2O --> 2K[Cr(H2O)2(C2O4)2].2H2O + CO2

Next, let's balance the potassium (K) atoms. There are four potassium atoms on the left side and two on the right. To balance this, we can put a coefficient of 2 in front of K2Cr2O7.

2K2Cr2O7 + H2C2O4.2H2O --> 4K[Cr(H2O)2(C2O4)2].2H2O + CO2

Now, let's balance the hydrogen (H) atoms. There are four hydrogen atoms from H2C2O4.2H2O on the left side and eight hydrogen atoms from K[Cr(H2O)2(C2O4)2].2H2O on the right side. To balance this, we can put a coefficient of 4 in front of H2C2O4.2H2O.

2K2Cr2O7 + 4H2C2O4.2H2O --> 4K[Cr(H2O)2(C2O4)2].2H2O + CO2

Finally, let's balance the carbon (C) and oxygen (O) atoms. There are four carbon atoms on the left side and eight carbon atoms on the right side. There are 12 oxygen atoms on the left side and also 12 on the right side. The equation is now balanced.

2K2Cr2O7 + 4H2C2O4.2H2O --> 4K[Cr(H2O)2(C2O4)2].2H2O + CO2

Now, let's move on to the second equation:

2. K2Cr2O7 + H2C2O4.2H2O --> K[Cr(H2O)2(C2O4)2].3H2O + CO2

Using a similar approach, we can balance this equation as well. The steps are as follows:

- Balance the chromium (Cr) atoms.
- Balance the potassium (K) atoms.
- Balance the hydrogen (H) atoms.
- Balance the carbon (C) and oxygen (O) atoms.

By following these steps, you should be able to balance the equation.