A dioxin-contaminated water source contains 0.052% dioxin by mass. How much dioxin (in g) is present in 4.2 liters of this water? (Assume the solution density is 1.00 g/mL.)
recall that density is mass over volume, or
d = m/V
substituting,
1 = m / 4200
m = 4200 g H2O
to get the mass of dioxin, we just multiply its percent mass:
4200 * 0.00052 = 2.184 g dioxin
hope this helps~ :)
To find the amount of dioxin in 4.2 liters of water, we'll first need to calculate the total mass of the solution.
Given that the density of the solution is 1.00 g/mL, we know that 1 liter of this water weighs 1 kilogram or 1000 grams. So, 4.2 liters of water will have a mass of 4.2 x 1000 = 4200 grams.
Now, we need to find the mass of dioxin in this water. We are told that the water contains 0.052% dioxin by mass. This means that for every 100 grams of the solution, 0.052 grams will be dioxin.
To calculate the mass of dioxin in 4200 grams of water, we can use the following equation:
Mass of dioxin = (0.052 / 100) x 4200
To simplify the calculation, let's first find the value of (0.052 / 100):
0.052 / 100 = 0.00052
Now we can substitute this value back into the equation:
Mass of dioxin = 0.00052 x 4200
Calculating the above:
Mass of dioxin = 2.184 grams
Therefore, 4.2 liters of dioxin-contaminated water would contain approximately 2.184 grams of dioxin.
To calculate the amount of dioxin in 4.2 liters of water, we need to use the mass percent of dioxin and the density of the water.
Step 1: Convert liters to milliliters.
1 liter = 1000 milliliters
4.2 liters = 4.2 * 1000 = 4200 milliliters
Step 2: Calculate the mass of the water.
Mass = Volume × Density
Mass = 4200 mL × 1.00 g/mL
Mass = 4200 grams
Step 3: Calculate the mass of dioxin in the water.
Mass of dioxin = Mass of water × Mass percent of dioxin
Mass of dioxin = 4200 grams × 0.052%
Mass of dioxin = 4200 grams × 0.00052
Mass of dioxin = 2.184 grams
Therefore, there are 2.184 grams of dioxin in 4.2 liters of water contaminated with 0.052% dioxin.