3(2x-5)greater eqal sign x+15

here!

3(2x-5) > x+15

6x - 15 > x + 15
combining similar terms,
6x - x > 15 + 15
5x > 30
x > 6

hope this helps~ :)

-7(x-5)> 35-7x

To solve the inequality 3(2x-5) ≥ x+15, we can follow these steps:

1. Expand the parentheses on the left side of the inequality:
6x - 15 ≥ x + 15

2. Group the x terms together by subtracting x from both sides:
6x - x - 15 ≥ x - x + 15
5x - 15 ≥ 15

3. Add 15 to both sides of the inequality:
5x - 15 + 15 ≥ 15 + 15
5x ≥ 30

4. Divide both sides of the inequality by 5 to isolate x:
(5x)/5 ≥ 30/5
x ≥ 6

Therefore, the solution to the inequality 3(2x-5) ≥ x+15 is x ≥ 6.