3(2x-5)greater eqal sign x+15
here!
3(2x-5) > x+15
6x - 15 > x + 15
combining similar terms,
6x - x > 15 + 15
5x > 30
x > 6
hope this helps~ :)
-7(x-5)> 35-7x
To solve the inequality 3(2x-5) ≥ x+15, we can follow these steps:
1. Expand the parentheses on the left side of the inequality:
6x - 15 ≥ x + 15
2. Group the x terms together by subtracting x from both sides:
6x - x - 15 ≥ x - x + 15
5x - 15 ≥ 15
3. Add 15 to both sides of the inequality:
5x - 15 + 15 ≥ 15 + 15
5x ≥ 30
4. Divide both sides of the inequality by 5 to isolate x:
(5x)/5 ≥ 30/5
x ≥ 6
Therefore, the solution to the inequality 3(2x-5) ≥ x+15 is x ≥ 6.