posted by Dwayne
Law of Gravitation- Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected.
The gravitational constant for g is, G = 6.67428*10^-11 m^3 Kg^-1 s^-2
Please answer the question fully and please give any helpful websites, thankyou.
Also I know calculus.
Then set the initial KEnergy equal to the potential energy at the surface of EArth.
1/2 mv^2= GMe*m/re
solve for escape velocity, v
v^2 = 2Mg/r + (u^2 -2Mg/d )
Is that right
Why did you make it so complicated?
1/2 m v^2=GMe m/re
take the square root of each side.