Post a New Question

Chemistry

posted by .

A 16.6 mL portion of an HBr solution of unknown strength is diluted to exactly 247 mL. If 102.1 mL of this diluted solution requires 87.8 mL of 0.37 M NaOH to achieve complete neutralization, what was the strength of the original HBr solution?

  • Chemistry -

    NaOH + HBr ==> NaBr + H2O

    moles NaOH used in the titration = M x L = 0.37 x 0.0878 = 0.03249.
    Using the balanced equation above, convert moles NaOH to moles HBr. The coefficients are 1:1; therefore, moles HBr = 0.03249
    That = the moles in the 102.1 mL sample. How much was in the 247 mL. That will be
    0.03249 x (247/102.1) = ?? moles HBr. That = the number of moles HBr in the 16.6 mL original sample.
    Then M = moles/L soln.

  • Chemistry -

    just for clarification,it's
    ?? moles HBr/original sample (which is 16.6ml)
    right?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    An aspirin tablet weighing 0.502 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. …
  2. chemistry

    An aspirin tablet weighing 0.502 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. …
  3. chemistry

    An aspirin tablet weighing 0.475 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. …
  4. college chemistry

    An aspirin tablet weighing 0.502 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. …
  5. Chemistry

    An aspirin tablet weighing 0.475 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. …
  6. chem

    A 27.4 mL sample of an unknown HClO4 solution requires 45.4 mL of 0.101 M NaOH for complete neutralization. What was the concentration of the unknown HClO4 solution?
  7. chem

    A 26.8 mL sample of an unknown HClO4 solution requires 46.8 mL of 0.101 M NaOH for complete neutralization. What was the concentration of the unknown HClO4 solution?
  8. chemistry

    A 15.0 ml sample of an unknown HClO4 solution requires 50.3 ml if 0.101 M NaOH for complete neutralization. What was the concentration of the unknown HClO4 solution?
  9. chemistry

    A 15.0 ml sample of an unknown HClO4 solution requires 50.3 ml if 0.101 M NaOH for complete neutralization. What was the concentration of the unknown HClO4 solution?
  10. chemistry

    A 15.0 ml sample of an unknown HClO4 solution requires 50.3 ml if 0.101 M NaOH for complete neutralization. What was the concentration of the unknown HClO4 solution?

More Similar Questions

Post a New Question