physics 152

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The force exerted by the wind on the sails of a sailboat is 500 N north. The water exerts a force of 150 N east. If the boat (including its crew) has a mass of 290 kg, what are the magnitude and direction of its acceleration?

  • physics 152 -

    Forces North = 500
    Force East = 150

    acceleration North = 500/290 = 1.72 m/s^2
    acceleration East = 150/290 = .517 m/s^2

    magnitude = sqrt(1.72^2+.517^2)
    = 1.80 m/s^2

    tan of angle north of east = 1.72/.517
    so direction = 73.3 deg N of E
    or
    16.7 deg East of North

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