NaOH(aq)+H3PO4(aq)�¨Na3PO4(pq)+H2O(l)
Please help.
3NaOH(aq)+H3PO4(aq) ==>Na3PO4(aq)+3H2O(l)
Did you want this balanced. I have corrected the symbolism for the arrow and corrected the aq (from pq for Na3PO4.
Yes I have trouble with balancing equations(in general).
Don't make it harder than it is. It's just a matter of counting. Here is how I do the NaOH + H3PO4.
NaOH + H3PO4 ==> Na3PO4 + H2O
1. Look at the equation. The first thing I see is 3Na on the right so I make 3NaOH on the left to balance Na. I also note the 1 PO4 on the right which means the 1 now for H3PO4 should be correct.
2. With NaOH, H3PO4, and Na3PO4 now set, that leaves only one item which is H2O. Count how many H atoms on the left. I see 6. That means 3H2O.
3. Then I check everything to make sure it is balanced.
3Na on left and right
1 PO4 on left and right
6 H on left and right
3 O atoms (excluding those due to PO4) on left and right. You CAN count all of the O atoms but I think it makes it a little easier if we keep PO4 together.
Certainly! It seems like you have a chemical equation that represents a reaction between sodium hydroxide (NaOH) and phosphoric acid (H3PO4) to form sodium phosphate (Na3PO4) and water (H2O).
To understand this equation better, we need to balance it. Balancing a chemical equation involves ensuring that the same number of atoms of each element are present on both sides of the equation.
Here's how you can balance this equation step by step:
Step 1: Start by identifying the atoms that are present on both sides of the equation. In this case, we have Na, H, O, and P.
Step 2: Balance the atoms that appear in the least number of molecules first. In this case, let's start with phosphorus (P). We have one P atom on the reactant side and one on the product side, so the P atoms are already balanced.
Step 3: Next, balance the hydrogen (H) atoms. We have three H atoms in H3PO4 and two H atoms in H2O on the left side. To equalize the number of H atoms, we can add a coefficient of 2 in front of H2O, which gives us 2H2O.
The equation now looks like this:
NaOH(aq) + H3PO4(aq) → Na3PO4(aq) + 2H2O(l)
Step 4: Finally, balance the sodium (Na) and oxygen (O) atoms. We have one Na atom on the left side and three Na atoms on the right side, so we need to add a coefficient of 3 in front of NaOH.
The balanced equation is:
3NaOH(aq) + H3PO4(aq) → Na3PO4(aq) + 2H2O(l)
Now we have a balanced chemical equation that represents the reaction between NaOH and H3PO4 to form Na3PO4 and H2O.