Use polynomial long division to divide
-9x3 – 18x2 – 11x – 2
divide by?
To use polynomial long division to divide the polynomial -9x^3 - 18x^2 - 11x - 2, you will need to divide it by another polynomial, typically in the form of (ax^2 + bx + c). Since you have not specified the divisor, I will assume it is a quadratic polynomial.
Let's say the divisor is in the form of (mx^2 + nx + p). The steps to perform polynomial long division are as follows:
Step 1: Arrange the dividend and divisor in descending order of exponents.
The dividend: -9x^3 - 18x^2 - 11x - 2
The divisor: mx^2 + nx + p
Step 2: Divide the first term of the dividend by the first term of the divisor.
In this case, divide -9x^3 by mx^2 to get -9x^3 / mx^2 = (-9/m)x^(3 - 2) = -9x.
Step 3: Multiply the divisor by the quotient obtained in Step 2. Place the result below the dividend, aligning like terms.
(-9x)(mx^2 + nx + p) = -9mx^3 - 9nx^2 - 9px
Place this below the dividend:
-9x
-------------------
-9mx^3 - 9nx^2 - 9px - 11x - 2
Step 4: Subtract the result obtained in Step 3 from the original dividend.
(-9x^3 - 18x^2 - 11x - 2) - (-9mx^3 - 9nx^2 - 9px) = (-9x^3 + 9mx^3) + (-18x^2 + 9nx^2) + (-11x + 9px) - 2
Simplifying this, we get:
(9m - 9)x^3 + (9n - 18)x^2 + (9p - 11)x - 2
Step 5: Repeat Steps 2-4 with the simplified polynomial obtained in Step 4.
Continue the process of dividing, multiplying, subtracting, and repeating with the simplified polynomial until you reach the lowest degree term or until the degree of the dividend is smaller than the degree of the divisor.
Keep in mind that since I don't have the specific divisor, the process above is a general explanation of polynomial long division. You would need to substitute the coefficients of your divisor into the steps provided to perform the actual division in your question.