Find the coordinates of the vertex of the graph of f(x)=2x^2+10x-17.
find the zeroes:
2x^2+10x-17=0
x= (-10+-sqrt(100+136))/4
x= (-2.5+-3.84)
x= -6.34; 1.34
so halfway between those is the vertex,or at -2.5
2x^2+10x-17=0
x= (-10+-sqrt(100+136))/4
x= (-2.5+-3.84)
x= -6.34; 1.34
so halfway between those is the vertex,or at -2.5