There is a net passage of 4.5 1018 electrons by a point in a wire conductor in 0.26 s. What is the current in the wire?
(# of electrons)*(electron charge)/time
e = 1.6*10^-19 Coulombs
To find the current in the wire, you can use Ohm's Law equation: I = Q/t, where I is the current, Q is the charge, and t is the time.
Given, the net passage of 4.5 x 10^18 electrons in 0.26 seconds.
Now, we need to determine the charge that passed through the point in the wire.
Since each electron has a charge of 1.6 x 10^-19 C (Coulombs), we can calculate the total charge by multiplying the number of electrons by the charge of each electron.
Total charge (Q) = (4.5 x 10^18) x (1.6 x 10^-19 C)
Now, let's calculate Q:
Q = (4.5 x 10^18) * (1.6 x 10^-19) C
Q = 7.2 x 10^-1 C
Using Ohm's Law equation:
I = Q/t
Substituting the values:
I = (7.2 x 10^-1 C) / (0.26 s)
I = 2.77 A
Therefore, the current in the wire is 2.77 Amperes (A).