College chemistry

posted by .

A buffer that consists of a mixture of NaH2PO4 and K2HPO4 has a pH of 6.73. The (HPO4)/(H2PO4) ratio in this buffer is what? If (k1,k2,and k3 for H3PO4 are 7.1x10^-3, 6.2x10^-8, and 4.5x10^-13 respectively)

  • College chemistry -

    Substitute the pH and pKa into
    pH = pKa + log(base)/(acid) and solve for the ratio of (base)/(acid).

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chem

    I posted a question earlier that I was having trouble with, but I was unable to attempt to try it again for several days after posting. The question was: A buffer is made up of .300 L each of .500 M KH2PO4 and .317 M K2HPO4. Assuming …
  2. chemistry

    a buffer is prepared by combining 10.0g of NaH2PO4 wiht 150mL of 0.20M NaOH and diluting to 2.0L. What is the pH of the buffer, Ka H2PO4-= 6.2x10-8
  3. chemistry 2

    which of the following has the highest bugger capacity?
  4. College Chem 2

    which of the following has the highest buffer capacity?
  5. Chem 2

    Which of the following has the highest buffer capacity?
  6. Chemistry

    H3PO4 Ka1= 7.5x10^-3 Ka2= 6.2x10^-8 Ka3=4.2x10-^13 Explain how you will make a buffer with a pH of 11.80 using solid Na2HPO4 and either 2.00 M NaOH or 2.00 M HCL. The most concentrated component should have a concentration of 0.50 …
  7. Science

    The Ka for the H2PO4–/HPO42– buffer is given by the equation: Ka= ([HPO4^-2]gamma [H^+])/[H2PO4^-]=10^-7.20 What is the pH of a 2:3 mixture of H2PO4– to HPO42– at 0.10 M ionic strength?
  8. chemistry

    Problem: Need to prepare a 250 mL buffer of pH 7.00 using equimolar K2HPO4 and KH2PO4 solutions. Ka for phosphoric acid: Ka1=7.2 x 10^-3 Ka2=6.3 x 10^-8 Ka3=4.2 x 10^-13 I though the hard part of this was picking the right equation/Ka …
  9. Chemistry

    A phosphate buffer solution contain 0.08 M K2HPO4 and 0.12 M KH2PO4. pKa values for H3PO4 are 2, 6.8, and 12.2. Calculate the concentrations of a) H3PO4 b) H2PO4- c) HPO42- d) H+ e) OH- f) K+
  10. Chemistry

    Phosphate can act as buffer: H2PO4- HPO4^2- + H+ The pKa of this equilibrium is 7.21. What is the ratio of H2PO4- to HPO4^2- at pH 7.0?

More Similar Questions