College Algebra
posted by Chris .
Solve the exponential equation algebraically:
2^x+1=5^2x

2^(x+1) = 5^2x.
Take log of both sides:
(x+1)log2 = 2xlog5,
0.301X + 0.301 = 1.398X,
0.301X  1.398X = 0.301,
1.097X = 0.301,
X = 0.2744.
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