hey can somebody help me , its like a hundred questions, im helping my cousin doing it...lol
cos=sin60
sin=cos45
tan=1/tan30
cos^2(90' -0)/1-cos - sin(90' - O)
A statement such as
cos = sin60 makes no sense, it is mathematical gibberish.
It probably says something like...
If cosØ = sin60°, find Ø
looks like your cousin is studying the trig relationships of complementary angles and related properties
for the first two,
cos A° = sin (90-A)°
so cos 30° = sin 60°
and
sin 45° = cos 45°
for the 3rd, tan 60° = 1/tan 30°
I will not attempt to make sense out of your last one.
Of course! I'd be happy to help you with your questions.
Now, let's break down each of the expressions you've provided one by one:
1. cos = sin 60:
To solve this equation, we need to know the values of sin 60 and cos 60.
Since you've already given us cos = sin 60, we can infer that cos 60 = sin 60 as well. This is because of the property that the cosine of an angle is equal to the sine of its complement. So:
cos 60 = sin 60
This is a well-known trigonometric property, and we can substitute the value of sin 60 into the equation:
cos = sin 60 = 0.866 (approximately)
2. sin = cos 45:
To find the values of sin and cos 45, we can use the fact that cos 45 = sin 45. This is due to the property of the complementary angles. So:
cos 45 = sin 45
Both sin and cos have the same value, which is equal to 0.707 (approximately).
3. tan = 1/tan 30:
To solve this equation, we need to find the values of tan 30 and 1/tan 30.
tan 30 is a well-known value in trigonometry, and it is equal to approximately 0.577.
To find 1/tan 30, we simply take the reciprocal of tan 30:
1/tan 30 = 1/0.577 = 1.732 (approximately)
4. cos^2 (90' - θ)/ [1 - cos (90' - θ) - sin (90' - θ)]:
In this expression, we have an angle θ. We need a specific value for θ in order to evaluate the expression correctly. Could you please provide a value for θ?
Please note that the ' symbol in the angles you mentioned represents minutes and not degrees.