Help me please wether i d0ne it right,what is the mass of calcium carbonate is required to react with sulfur dioxide produced by burning 1000 kgs of coal that contain 5% sulfur by mass?tnx
To calculate the mass of calcium carbonate required to react with sulfur dioxide produced by burning coal, we need to follow a few steps.
Step 1: Determine the amount of sulfur dioxide produced
Since the coal contains 5% sulfur by mass and we have 1000 kgs of coal, we can calculate the mass of sulfur dioxide produced. The calculation is as follows:
Mass of sulfur = (5/100) * 1000 kg coal
= 50 kg
Step 2: Find the molar mass of sulfur dioxide
The molar mass of sulfur dioxide (SO2) is calculated by adding the atomic masses of sulfur (S) and oxygen (O):
Molar mass of S = 32.06 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of SO2 = (1 * molar mass of S) + (2 * molar mass of O)
= (1 * 32.06) + (2 * 16.00) g/mol
= 64.12 g/mol
Step 3: Calculate the number of moles of sulfur dioxide
To find the number of moles of SO2, divide the mass of sulfur dioxide (found in step 1) by its molar mass (found in step 2):
Number of moles of SO2 = Mass of sulfur dioxide / Molar mass of SO2
= 50 kg / (64.12 g/mol)
= (50 * 1000 g) / (64.12 g/mol)
= 780.28 mol
Step 4: Determine the balanced chemical equation
The balanced chemical equation for the reaction between calcium carbonate (CaCO3) and sulfur dioxide (SO2) is as follows:
CaCO3 + SO2 -> CaSO3 + CO2
Step 5: Utilize stoichiometry to find the mass of calcium carbonate
From the balanced equation, we see that for every 1 mole of CaCO3, 1 mole of SO2 is required. Therefore, the number of moles of CaCO3 needed is equal to the number of moles of SO2:
Number of moles of CaCO3 = 780.28 mol
Finally, we need to find the mass of calcium carbonate by multiplying the number of moles by its molar mass:
Mass of CaCO3 = Number of moles of CaCO3 * Molar mass of CaCO3
The molar mass of calcium carbonate (CaCO3) can be calculated as:
Molar mass of Ca = 40.08 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of CaCO3 = (1 * molar mass of Ca) + (1 * molar mass of C) + (3 * molar mass of O)
= (1 * 40.08) + (1 * 12.01) + (3 * 16.00) g/mol
= 100.09 g/mol
Substituting the values into the equation, we get:
Mass of CaCO3 = 780.28 mol * 100.09 g/mol
= 78074.82 g or 78.07 kg
Therefore, approximately 78.07 kg of calcium carbonate is required to react with the sulfur dioxide produced by burning 1000 kg of coal containing 5% sulfur by mass.