The physics of an electron falling through a potential difference.
How much kinetic energy will an electron gain (joules) if it falls through a potential difference of 350 V?
KE gain = e*V,
where e is the electron charge in Coulombs, and V = 350 volts
It may be helpful to recall that
1 Volt = 1 Joule per Coulomb
To calculate the kinetic energy gained by an electron falling through a potential difference, we can use the equation:
KE = qV
Where KE is the kinetic energy gained, q is the charge of the electron, and V is the potential difference.
The charge of an electron, q, is approximately 1.6 x 10^(-19) C (coulombs).
Given that the potential difference, V, is 350 V, we can substitute the values into the equation:
KE = (1.6 x 10^(-19) C) x (350 V)
Calculating this multiplication:
KE = 5.6 x 10^(-17) Joules
Therefore, an electron falling through a potential difference of 350 V will gain approximately 5.6 x 10^(-17) Joules of kinetic energy.
To calculate the kinetic energy gained by an electron falling through a potential difference, you need to use the equation:
KE = qV
Where:
KE is the kinetic energy gained (in joules),
q is the charge of the electron (in coulombs), and
V is the potential difference (in volts).
The charge of an electron is approximately -1.6 x 10^-19 coulombs.
So, to determine the kinetic energy gained, you can substitute these values into the equation:
KE = (-1.6 x 10^-19 C) * (350 V)
Now, let's calculate it:
KE = -5.6 x 10^-17 J
Therefore, an electron will gain approximately -5.6 x 10^-17 joules of kinetic energy when it falls through a potential difference of 350 V.