How do I calculate the amount of heat needed to convert 96g of ice at -24 degrees celciua to water at 28 degrees celciua?
see below http://www.jiskha.com/display.cgi?id=1303865666
To calculate the amount of heat needed to convert ice to water, you can use the formula:
Q = m * ΔHf
Where:
Q = Heat energy (in joules)
m = Mass of the substance (in grams)
ΔHf = Heat of fusion (specific heat) of the substance (in J/g)
Step 1: Calculate the heat required to raise the temperature of ice from -24°C to 0°C.
Q1 = m * c * ΔT1
Where:
m = Mass of ice (in grams)
c = Specific heat capacity of ice (2.09 J/g°C)
ΔT1 = Change in temperature (0°C - (-24°C) = 24°C
Q1 = 96g * 2.09 J/g°C * 24°C
Step 2: Calculate the heat required to melt the ice at 0°C to water at 0°C.
Q2 = m * ΔHf
Where:
m = Mass of ice (in grams)
ΔHf = Heat of fusion of ice (333.55 J/g)
Q2 = 96g * 333.55 J/g
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 28°C.
Q3 = m * c * ΔT2
Where:
m = Mass of water (in grams)
c = Specific heat capacity of water (4.18 J/g°C)
ΔT2 = Change in temperature (28°C - 0°C) = 28°C
Q3 = 96g * 4.18 J/g°C * 28°C
Step 4: Add up the three calculated heats to find the total amount of heat required.
Q = Q1 + Q2 + Q3
Make the necessary calculations to find the final answer.
To calculate the amount of heat needed to convert 96g of ice at -24 degrees Celsius to water at 28 degrees Celsius, we can follow these steps:
Step 1: Calculate the heat required to raise the temperature of the ice from -24 degrees Celsius to 0 degrees Celsius.
The specific heat capacity of ice is 2.09 J/g°C. The formula for calculating heat is:
Q = m * c * ΔT
where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the mass (m) is 96g, the specific heat capacity (c) is 2.09 J/g°C, and the change in temperature (ΔT) is 0 - (-24) = 24°C.
So, Q1 = 96g * 2.09 J/g°C * 24°C
Step 2: Calculate the heat required to melt the ice at 0 degrees Celsius.
The heat of fusion of ice is 333.5 J/g.
Q2 = m * ΔHf
where ΔHf is the heat of fusion.
In this case, the mass (m) is 96g and the heat of fusion (ΔHf) is 333.5 J/g.
So, Q2 = 96g * 333.5 J/g
Step 3: Calculate the heat required to raise the temperature of the water from 0 degrees Celsius to 28 degrees Celsius.
The specific heat capacity of water is 4.18 J/g°C.
Q3 = m * c * ΔT
In this case, the mass (m) is 96g, the specific heat capacity (c) is 4.18 J/g°C, and the change in temperature (ΔT) is 28°C - 0°C = 28°C.
So, Q3 = 96g * 4.18 J/g°C * 28°C
Step 4: Add up the three quantities of heat:
Total heat required (Q_total) = Q1 + Q2 + Q3
Hope this helps! Let me know if you have any further questions.