1How would each of the following affect the accuracy of the calculated neutralizing power of antaid (too high, too low, no effect) explain
a)The actacid tablet was not cut exactly in half before weighing
b)The solution mixture of reacted antacid and excess HCL spattered out of the flask during boiling
2 Calculate the neutralizing powe of 1 gram of pure NaHCO3 (FW=84.02g/mol)
a) If the actacid tablet was not cut exactly in half before weighing, it would likely have an impact on the accuracy of the calculated neutralizing power of the antacid. If the tablet is not divided evenly, the amount of active ingredient in each half may not be equal. This can lead to an unequal neutralizing effect when the tablet is added to an acid solution. The calculated neutralizing power may be too high or too low depending on whether the uneven division results in an excess or a deficiency of the active ingredient.
b) If the solution mixture of reacted antacid and excess HCl spattered out of the flask during boiling, it would also affect the accuracy of the calculated neutralizing power. This is because some of the solution would be lost, leading to a decrease in the total amount of acid and antacid in the flask. As a result, the neutralizing power would be underestimated, giving a lower calculated value.
To calculate the neutralizing power of 1 gram of pure NaHCO3 (sodium bicarbonate), we need to use its molar mass.
Given:
- Mass of NaHCO3 = 1 gram
- Formula weight (FW) of NaHCO3 = 84.02 g/mol
To calculate the neutralizing power, we need to determine the moles of NaHCO3. We can do this by dividing the given mass (in grams) by the molar mass:
Moles of NaHCO3 = Mass / FW
Moles of NaHCO3 = 1 gram / 84.02 g/mol
Now, divide the moles of NaHCO3 by 2 to take into account that NaHCO3 neutralizes 2 moles of HCl per mole of NaHCO3:
Moles of HCl neutralized = Moles of NaHCO3 / 2
The neutralizing power is the moles of HCl neutralized per gram of NaHCO3:
Neutralizing power = Moles of HCl neutralized / Mass of NaHCO3
Plug in the values:
Neutralizing power = (Moles of NaHCO3 / 2) / Mass of NaHCO3
Neutralizing power = [(1 gram / 84.02 g/mol) / 2] / 1 gram
Perform the calculations to get the final answer.