I need to know the most polar bond in each molecule. HSCH2CH2OH / HC12F / HOCH2CH2NH2
Look up the electronegativities of the two atoms and subtract. The greater difference will be due to the greater polarity.
To determine the most polar bond in each molecule, you need to consider the electronegativity values of the atoms involved in the bond. The greater the difference in electronegativity, the more polar the bond will be.
1. HSCH2CH2OH:
The molecule HSCH2CH2OH consists of hydrogen (H), sulfur (S), carbon (C), oxygen (O), and hydrogen (H). To determine the most polar bond, we need to compare the electronegativity values of the atoms involved in each bond.
- H-S: The electronegativity of hydrogen (H) is 2.2, and the electronegativity of sulfur (S) is 2.58. Therefore, the electronegativity difference is 0.38.
- C-S: The electronegativity of carbon (C) is 2.55, and the electronegativity of sulfur (S) is 2.58. The electronegativity difference is 0.03.
- C-O: The electronegativity of carbon (C) is 2.55, and the electronegativity of oxygen (O) is 3.44. The electronegativity difference is 0.89.
- O-H: The electronegativity of oxygen (O) is 3.44, and the electronegativity of hydrogen (H) is 2.2. The electronegativity difference is 1.24.
Comparing the electronegativity differences, we see that the O-H bond has the highest difference (1.24), making it the most polar bond in HSCH2CH2OH.
2. HC12F:
The molecule HC12F consists of hydrogen (H), carbon (C), and fluorine (F). Let's compare the electronegativity values of the atoms involved in each bond.
- H-C: The electronegativity of hydrogen (H) is 2.2, and the electronegativity of carbon (C) is 2.55. Therefore, the electronegativity difference is 0.35.
- C-F: The electronegativity of carbon (C) is 2.55, and the electronegativity of fluorine (F) is 3.98. The electronegativity difference is 1.43.
Comparing the electronegativity differences, we see that the C-F bond has the highest difference (1.43), making it the most polar bond in HC12F.
3. HOCH2CH2NH2:
The molecule HOCH2CH2NH2 consists of hydrogen (H), oxygen (O), carbon (C), and nitrogen (N). Let's compare the electronegativity values of the atoms involved in each bond.
- H-O: The electronegativity of hydrogen (H) is 2.2, and the electronegativity of oxygen (O) is 3.44. Therefore, the electronegativity difference is 1.24.
- O-C: The electronegativity of oxygen (O) is 3.44, and the electronegativity of carbon (C) is 2.55. The electronegativity difference is 0.89.
- C-N: The electronegativity of carbon (C) is 2.55, and the electronegativity of nitrogen (N) is 3.04. The electronegativity difference is 0.49.
Comparing the electronegativity differences, we see that the H-O bond has the highest difference (1.24), making it the most polar bond in HOCH2CH2NH2.