Suppose you tired to carry out a double-replacement reaction by mixing together equal volumes of a solution that contained dissolved NaF and a solution that contained dissolved NaCl. Would you expect a reaction, if so write the balanced chemical equation?

I answered this for you below.

To determine if a reaction would occur when mixing solutions of NaF and NaCl, we need to consider the solubility of the resulting compounds and the possibility of a double-replacement reaction.

First, let's check the solubility of the compounds. NaF, or sodium fluoride, is highly soluble in water. NaCl, or sodium chloride, is also highly soluble in water. Therefore, both NaF and NaCl would dissociate completely into their respective ions in solution: Na+ and F- for NaF, and Na+ and Cl- for NaCl.

Next, we evaluate if a double-replacement reaction is possible. In a double-replacement reaction, the cations and anions from the two compounds will swap, forming new compounds. However, for a reaction to take place, one of the products must be insoluble in water and therefore precipitate out.

In this case, both NaF and NaCl form soluble compounds. When mixed together, Na+ and F- would combine with Na+ and Cl-, respectively, resulting in NaCl and NaF as the products. Since both are soluble, no observable reaction occurs.

Therefore, the balanced chemical equation for the mixing of NaF and NaCl solutions would be:

NaF(aq) + NaCl(aq) -> NaCl(aq) + NaF(aq)

Note that the "->" symbol represents a reaction or reaction direction, and (aq) stands for an aqueous solution.