# college chem

posted by .

The cation M2+ reacts with NH3 to form a series of complex ions as follows:
M2+ + NH3 M(NH3)2+ K1 = 102
M(NH3)2+ + NH3 M(NH3)2
2+ K2 = 103
M(NH3)2
2+ + NH3 M(NH3)3
2+ K3 = 102
A 1.0 × 10–3 mol sample of M(NO3)2 is added to 1.0 L of 15.0 M NH3 (Kb = 1.8 × 10–5). What is the dominant species in this
solution? EXPLAIN. (don’t have to calculate here)
a) M2+
b) M(NH3)2+
c) M(NH3)2
2+
d) M(NH3)3
2+
e) M(NO3)2

• college chem -

the answer is D - not sure why though but that is the answer according to another site.

## Similar Questions

1. ### Honors Chemistry

"How many grams of NH3 can be produced from the reaction of 28 g of N2 and 25 g of H2?
2. ### chemistry

for the complex ion equilibria between AgCl and NH3, why does NH3 replace Cl- and how do we know that we have to add 2 infront of NH3?
3. ### chemistry

for the complex ion equilibria between AgCl and NH3, why does NH3 replace Cl- and how do we know that we have to add 2 infront of NH3?
4. ### chemistry

what is the Molarity (M) of a 0.87m aqueous solution of ammonia, NH3?
5. ### Chemistry

Consider this equilibrium N2(g) + H2(g) <==> NH3(g) +94 kJ The equilibrium law exoression for the balanced chemical equationwould be A. [N2][H2]/[NH3] B. [NH3]/[H2][N2] C. [NH3]2/[H2][N2] D. [NH3]2/[H2]3[N2] E. 2[NH3]2/3[H2]3[N2]
6. ### Chemistry

in the presence of NH3, Cu+2 forms the complex ion [Cu(NH3)4]+2. If the equilibrium concentrations of Cu+2 and [Cu(NH3)4]+2 are 1.8x10^-17M and 1.0x10^-3M respectively, in a 1.5 M NH3 solution, calculate the value for the overall formation …
7. ### chemistry

50.0 mL of a 0.00200 M Cd^2+ solution is titrated with 0.00400 M EDTA in the presence of 0.0750 M NH3 buffered at pH = 9.00. Determine pCd^2+ when 28.5 mL of EDTA solution have been added. Cd^2+ + Y^4- ?
8. ### chemistry

Determination of Kf of Cu(NH3)4 (aq) with given 10mL of 6M NH3 mix with 40mL of 1M Cu. This is what I have so far: nCu= .040L x 1= .040mol nNH3= .010L x 6= .060mol Cu^2+ + 4NH3 -> Cu(NH3)4 .040 .06 0 -.040 4(-.040) +.040 0 -.1 .040 …
9. ### Chem

Determine the heat evolved (in kJ and in J) when 10.0 g of NH3(g) are created. Show all units and conversion factors. 10.0 gNH3 (1 mole nh3/17.0 g nh3)(-46.11 kj/1 mol nh3) = 23.11 kj -27.12 kj (1000j/1kj) -27,120 Is this correct?
10. ### chem

Calculate the equilibrium concentration of NH3,Cu^2+,[ Cu(NH3)]^2+ ,[Cu(NH3)2]^2+,[Cu(NH3)3]^2+,and[Cu(NH3)4]^2+ in a solution made by mixing 500.0 ml of 3.00 M NH3 with 500.0 ml of 2.00*10^-3 M Cu(NO3)2. The sequential equilibria …

More Similar Questions