what is the net ionic equation for tin + copper 2 sulfate?
Sn(s) + Cu^2+ ==>Cu(s) + Sn^2+(aq)
Please note that copper 2 sulfate is NOT the same as copper(II) sulfate.
To determine the net ionic equation for the reaction between tin and copper(II) sulfate, we need to identify the compounds and their respective ions present in the reaction.
The compound "tin" could refer to either tin(II) or tin(IV) ions. Assuming tin(II) is involved, it would have a +2 charge, and copper(II) sulfate (CuSO4) dissociates into copper(II) ions (Cu2+) and sulfate ions (SO42-).
The balanced chemical equation for the reaction can be written as follows:
Sn + CuSO4 → SnSO4 + Cu
To determine the net ionic equation, we need to remove any spectator ions that appear unchanged on both sides of the equation. In this case, the spectator ion is sulfate (SO42-).
So, the net ionic equation is:
Sn + Cu2+ → Sn2+ + Cu
This equation focuses only on the significant species participating in the reaction, neglecting the spectator ion.