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a stone is from the top of a tower 300m high and at the same time another stone is projected vertically upward with initial velocity 75m/s. calculate when and where the two stone meet

  • physics -

    Solve for the t when
    first stone height = second stone height
    300 - 4.9 t^2 = 75 t- 4.9 t^2

    The "4.9" is g/2, in m/s^2

    75 t = 300
    t = 4 seconds
    height = 300 - 4.9*16 = 226 m

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