physics
posted by irna .
a stone is from the top of a tower 300m high and at the same time another stone is projected vertically upward with initial velocity 75m/s. calculate when and where the two stone meet

Solve for the t when
first stone height = second stone height
300  4.9 t^2 = 75 t 4.9 t^2
The "4.9" is g/2, in m/s^2
75 t = 300
t = 4 seconds
height = 300  4.9*16 = 226 m
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