Question

Evaluate

log(base2)8-log(base2)12+log(base2)6

Answer 1

Use the laws of logarithm:

log(a)+log(b)=log(ab)
log(a)-log(b)=log(a/b)

so
log(base2)8-log(base2)12+log(base2)6
=log(base2)(8/12*6)
=log(base2)4
=2